A Bag Contains 6 Red Marbles 4 Blue Marbles

You draw 4 marbles out at random without replacement.

A bag contains 6 red marbles 4 blue marbles.

There are 8 6 48 ways of drawing blue then red so p 8 6 18 18 4 3 9 9 4 3 9 4 27 0 148148148 or just under 15. A marble is taken at random and replaced. Then a second marble is drawn. Another marble is taken from the bag.

You have 8 6 4 18 marbles each assumed to have a 1 18 probability of being drawn. A marble is drawn from the bag and is not replaced. P both are red 4 10 3 9 12 90 p both are blue 6 10 5 9 30 90 p both are of the same color 42 90. A bag contains 6 red marbles 7 blue marbles and 6 green marbles if one marble is randomly picked from the bag what is the probability that this is a blue marble.

Find p red or blue. Favorite answer 6 4 6 6 4 10 16. A bag contains 6 red marbles 6 white marbles and 4 blue. Work out the probability that the two marbles taken from the bag are the same color.

If a marble is randomly selected from the bag what is the probability that it is blue. A bag contains 6 red marbles 3 blue marbles and 5 green marbles. The problem asks for the probability of rr or bb. A bag contains 3 red marbles and 4 blue marbles.

A bag contains 6 red marbles 4 blue marbles 7 green marbles and 3 yellow marbles. There would be a 7 19 or 36 84. How do u do it. Given that you have bb.

Asked 01 09 17 a bag contains 4 red marbles and 5 blue marbles whats probability of randomly selecting a blue marble and then without replacing it selecting a red marble.