A Bag Of Marbles Contains 120 Red And Yellow Marbles

The first is replaced before the second is drawn.

A bag of marbles contains 120 red and yellow marbles.

The probability of choosing first red marble is 5 12 because there is not any replacement now 4 red marbles are remained and totally 11 marbles. A bag contains nine red marbles four green marbles three blue marbles and two yellow marbles. Y number of black marbles. Two marbles are drawn.

Let x number of red marbles. A handful of 5 marbles is grabbed from the bag. Asked 03 10 20 a bag contains yellow marbles and red marbles 16 in total. 2 put value of x in 1 we get put y 6 in 2 we get hence there are 114 red marbles in the bag.

P 3 10 7 9 2 8 p 7 120 since we were ask to find the probability of chosing 1 red 1 black and 1red marble without replacement after each draw we can use the fundamental method in finding the probability. A bag contains 70. Asked by lyla on april 18 2014. A bag contains 9 red marbles 8 white marbles and 6 blue marbles.

Calculate the expected value of the random variable. If there are only red and blue marbles and out of the 120 in total there are 80 blue marbles then there must be 120 80 40 red marbles. There are 3 red marbles and 7 black ma. The ratio between blue and red marbles is therefore.

Thus the probability of choosing the second red marble is 4 11. The probability of consecutively choosing two red marbles and a green marble without replacement. Which can be re expressed as. The number of different handfuls of 5 marbles with exactly 2 green and no yellow marbles is.

By dividing both sides by the common factor 40. A bag contains 4 yellow 2 red and 6 green marbles. The number of yellow marbles is 1 more than 2 times the number of red marbles. Learn more.

1 there are 19 red marbles every for black marble. A bag contains 120 marbles. A random variable assigns the number of red marbles to each outcome.